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Mathematics 16 Online
OpenStudy (anonymous):

Use the given graph to determine the limit, if it exists. A coordinate graph is shown with a horizontal line crossing the y axis at three that ends at the open point 2, 3, a closed point at 2, 1, and another horizontal line starting at the open point 2, -3. Find limit as x approaches two from the left of f of x. and limit as x approaches two from the right of f of x..

OpenStudy (anonymous):

OpenStudy (anonymous):

@e.mccormick

OpenStudy (agent0smith):

on the left of x=2, for example at x=1, what is the value of the function? ie what is y when x=1

OpenStudy (anonymous):

wait

OpenStudy (anonymous):

can you check this one first

OpenStudy (anonymous):

OpenStudy (anonymous):

Find limit as x approaches two from the left of f of x. and limit as x approaches two from the right of f of x..

OpenStudy (anonymous):

3; -3

OpenStudy (agent0smith):

Those are both correct :)

OpenStudy (anonymous):

okay now this one:

OpenStudy (anonymous):

Find limit as x approaches three from the left of f of x..

OpenStudy (agent0smith):

What y-value is the line approaching, as you follow from the left?

OpenStudy (anonymous):

2

OpenStudy (agent0smith):

Are you sure? As you get close to x=3, what is y getting close to?

OpenStudy (anonymous):

-10

OpenStudy (agent0smith):

I'm not sure where you're looking on the graph. Start from the left, and follow the line until you reach x=3.

OpenStudy (anonymous):

1

OpenStudy (agent0smith):

Good! :D

OpenStudy (anonymous):

so thats the answer?

OpenStudy (agent0smith):

Find limit as x approaches three from the left of f of x.. well, the line approaches y=1 when x approaches 3 from the left, yes? :)

OpenStudy (anonymous):

yes

OpenStudy (agent0smith):

There you go then! :)

OpenStudy (anonymous):

so thats my answer lolol

OpenStudy (agent0smith):

haha yes :) the limit is 1

OpenStudy (anonymous):

THANK YOU YOU ARE JESUS OKOAY

OpenStudy (agent0smith):

LOL I am Jesus! :D

OpenStudy (anonymous):

YOU ARE lolol help me tomorrow please???

OpenStudy (agent0smith):

hahahaha and sure

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