help! question in comments
\[4g ^{3}h \times 2g ^{8}h ^{2}\]
Simplify
@mathstudent55 help please?
I'm not sure what exponent is h supposed to have
{8g^11h3}
{8g^11h^3}
Regroup the factors: \( \Large 4g ^{3}h \times 2g ^{8}h ^{2}\) \( \Large =(4 \times 2) \times (g ^{3} \times g^8) \times (h \times h ^{2})\)
4 x 2 is easy For the g and h variables, use the rule \(\Large a^m \times a^n = a^{m + n} \)
Yeah, so far I have \[8g ^{11}\]
A plain h is the same as \(h^1\) .
So far so good.
Ahhhh! Okay that was what I was mostly mistaken in. So then it'll be 8g^11h^3 ?
Correct.
Thanks, would you mind helping me out with another expnent problem please?
\(\Large =(4 \times 2) \times (g ^{3} \times g^8) \times (\color{red}{h} \times h ^{2})\) \(\Large =(4 \times 2) \times (g ^{3} \times g^8) \times (\color{red}{h^1} \times h ^{2})\) \(\Large =8g^{11}h^3\)
sure, one more
Okay, I'll post it in another post so I can give you a medal
Great. Thanks.
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