help! question in comments

Question

ineedhelp10 · Answer

$$4g ^{3}h \times 2g ^{8}h ^{2}$$

ineedhelp10 · Answer

Simplify

ineedhelp10 · Answer

@mathstudent55 help please?

ineedhelp10 · Answer

I'm not sure what exponent is h supposed to have

anonymous · Answer

{8g^11h3}

anonymous · Answer

{8g^11h^3}

mathstudent55 · Answer

Regroup the factors:

$ \Large 4g ^{3}h \times 2g ^{8}h ^{2}$

$ \Large =(4 \times 2) \times (g ^{3} \times g^8) \times (h \times h ^{2})$

mathstudent55 · Answer

4 x 2 is easy

For the g and h variables, use the rule

$\Large a^m \times a^n = a^{m + n} $

ineedhelp10 · Answer

Yeah, so far I have $$8g ^{11}$$

mathstudent55 · Answer

A plain h is the same as $h^1$ .

mathstudent55 · Answer

So far so good.

ineedhelp10 · Answer

Ahhhh! Okay that was what I was mostly mistaken in. So  then it'll be 8g^11h^3 ?

mathstudent55 · Answer

Correct.

ineedhelp10 · Answer

Thanks, would you mind helping me out with another expnent problem please?

mathstudent55 · Answer

$\Large =(4 \times 2) \times (g ^{3} \times g^8) \times (\color{red}{h} \times h ^{2})$

$\Large =(4 \times 2) \times (g ^{3} \times g^8) \times (\color{red}{h^1} \times h ^{2})$

$\Large =8g^{11}h^3$

mathstudent55 · Answer

sure, one more

ineedhelp10 · Answer

Okay, I'll post it in another post so I can give you a medal

mathstudent55 · Answer

Great. Thanks.