Question

A problem about the distance between two different lines in two different planes from
http://saab.org

Answer 1

You are given two points
A and B
to get the distance AB you must do B-A

B-A

you should be able to do it

Answer 2

I know how to do it. I am just posting it for someone to try. You need to find the points so the distance between them is as small as possible.

Answer 3

@ganeshie8

Answer 4

using the hint,
f(s, t) =(2+3t-2s)^2 + (-6+7t-10s)^2+49

clearly the minimum value for this is 49; it occurs when :
2+3t-2s = 0
-6+7t-10s = 0

solving, (s, t) = (-2, -2)

the corresponding points on lines that give shortest distance are :
A = (5, 2, 4)
B = (5, 2, 11)

Answer 5

same method :)))

Answer 6

Yes

Answer 7

plz cud u type more qs like this :o
also if u dnt mind type qs on partial derivatives
, chain role ,tangent planes
also on multiple integral :D