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Chemistry 18 Online
OpenStudy (anonymous):

Need help with Redox half reaction

OpenStudy (aaronq):

im not sure there are guidelines for this, i'm pretty sure any redox reaction can take place in both media. you would have to be told whether it's in acid or base.

OpenStudy (anonymous):

oh dude thanks god your on k i need help with this redox half reaction

OpenStudy (anonymous):

Zn(s)+H^+(aq)---> Zn^2+(aq)+ H2(g)

OpenStudy (anonymous):

i know the oxidation numbers, do u want me to tell u?

OpenStudy (aaronq):

what exactly is giving you trouble with that half reaction?

OpenStudy (anonymous):

I need to balance it and i cannot balance the reduction half reaction which is H^+ --> H2

OpenStudy (anonymous):

wait i forgot the to add the the electron to that

OpenStudy (aaronq):

2H^+ + 2e --> H2

OpenStudy (anonymous):

k yea about that

OpenStudy (anonymous):

so ik that the oxidation reaction has 2 electron and you have to multiply the reduction by, but do you also have to multiply H2 by 2 as well or you just leave as it is.

OpenStudy (aaronq):

well the first step should be for you to balance the atoms (on both sides), which would leave you with 2H^+ -> H2, so even if you multiply it by 2, you'd still have a balanced equation. You need 2 electrons for each, the reduction and the oxidation, so there isn't a need to multiply anything.

OpenStudy (anonymous):

oh okay, i see i thought i had to multiply the reaction by 2 first. okay i got it thanks

OpenStudy (aaronq):

no problem, dude

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