I just need someone to tell me what they get for the test statistic, with their working out, so I know where I am going wrong please.
@agent0smith
this is what I did, it is wrong clearly lol
@Luigi0210 @e.mccormick
@Notamathgenius
I have no clue m8 sorry ;-;
@thomaster
@ybarrap
a) Null Hypotheses: \(\mu = \mu_0\) Alternative: \(\mu > \mu_0\) b) Compute the \(t\) value: $$ \large{ t = \frac{\overline{x} - \mu_0}{s/\sqrt{n}} } $$ Where \(\bar{x}=1065\), \(\mu_0=1050\), \(s=19\) and \(n=50\). c) Compare \(t\) to \(\large T_{critical}\): \(\large T_{critical}\) at the \(5\text{%}\) level is 1.6766: see - http://easycalculation.com/statistics/critical-t-test.php If \(t < T_{critical}\) then the manufacturer's claims are justified because you can not reject the null hypothesis and the difference is likely just due to random variation.
Can you see that? If not, I'll screenshot it for you.
(just in case)
ybarrap that gives me 5.58 on part b, but my lecturer has 1.537, and I don't know how... and considering the critical value is 1.645, 1.537 seems like the more logical answer. Any idea how I can get to that?
@ybarrap
this is my lecturers answer
I would have to say that the lecturer made an error -- you and I came up with the same result independently. The formula is pretty straight-forward and we all agree on all the other parameters.
Thank you, I have been getting mad at this alot, but I have never had a answer that high on a hypothesis test, I am inclined to believe there is something missing but we did get the same answer so thank you for helping
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