Question

calculus 2

Answer 1

Suppose F'(t) = cos(z^3)

Answer 2

Using FTC, we have
d/dt INT cos(z^3) DZ = d/dt [F(pi) - F(t)] = d/dt F(pi) - d/dt F(t)

Answer 3

Still stuck?

Answer 4

yea, can you put it in picture form since I'm having trouble reading that format

Answer 5

One second...

Answer 6

Can you see this?

Answer 7

yes

Answer 8

This should explain it well

Answer 9

why is it cos t^3 and not cos pi ^3?

Answer 10

We technically do not know what function F(t) is.

Answer 11

Do you want to know why d/dt F(pi) becomes 0?

Answer 12

because pi is a constant

Answer 13

i plugged int cos pi^3 and it says incorrect