Question

calculus 2

Answer 1

trig identity

Answer 2

by FTC, derivative and integral cancel eachother out and leave u wid :
sin(t^2) | evaluate between 1 and x^8

you should get :
sin(x^16) - sin(1)

Answer 3

What is FTC?

Answer 4

fundamental theorem of calculus

Answer 5

derivative of an integral gives u the function back

Answer 6

sin(x^16) - sin(1) was incorrect

Answer 7

yes, sin(1) derivative is 0. so it should go away

Answer 8

try this : 8x^7*sin(x^16)

Answer 9

Thank you. that worked

Answer 10

cool xD
did u get how i figured out that ha ? :)

Answer 11

you did f(b) - f(a) right?

Answer 12

ive just used the FTC correctly this time :-

d/dx (integral 1->x^8 sin(t^2) dt) = sin((x^8)^2) * d/dx(x^8)

Answer 13

Ok, I kinda see

Answer 14

sure ? let me knw if u need some explanantion..

Answer 15

have a look at this, when u get time :
http://www.wyzant.com/resources/lessons/math/calculus/integration/ftoc