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OpenStudy (anonymous):
Solve. check for extraneous solutions.
√ x+√ 2x=√ 2x
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OpenStudy (anonymous):
u'l get extraneous root when you square both sides but if you don't then u'l get no extraneous roots
OpenStudy (anonymous):
can you show it to me @divu.mkr
OpenStudy (anonymous):
x+2x +2x(sqrt2)= 2x
OpenStudy (anonymous):
not really can you help me out lol im bad at math
OpenStudy (mathstudent55):
Is this the problem?
\( \sqrt{x} + \sqrt{2x} = \sqrt{2x} \)
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OpenStudy (anonymous):
yes
OpenStudy (mathstudent55):
Then start by subtracting \( \sqrt{2x} \) from both sides. What do you get?
OpenStudy (anonymous):
-2 0 ?
OpenStudy (mathstudent55):
\(\sqrt{x} + \sqrt{2x} = \sqrt{2x}\)
\(\sqrt{x} = 0\)
Now square both sides,
x = 0
There's your solution.
OpenStudy (anonymous):
thanks a lot:)
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OpenStudy (mathstudent55):
You're welcome. We didn't square both sides, so we did not introduce any extraneous solutions.
OpenStudy (mathstudent55):
You're welcome.
OpenStudy (anonymous):
lol so whats next haha
OpenStudy (mathstudent55):
This problem is done. You can check the solution, x = 0, in the original equation and you'll see that it works.
OpenStudy (anonymous):
ow thanks again
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OpenStudy (mathstudent55):
You're welcome.
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