Check my answers Please I will fan and award a medal
11)
which comes out to (b-10)/(b-1) when simplified.
oh i see , i don't know how i did this wrong :( i must have factored wrong
quack ?
Next time, show your work like this so we can tell where the error was made. 12) Simplify the following: ((2 t)/(5)-(3 t)/(3))/(t/2+t/2) Combine t/2+t/2 into a single fraction. t/2+t/2 = (t+t)/2: ((2 t)/5-(3 t)/(3))/((t+t)/2) Add like terms in t+t. t+t = 2 t: ((2 t)/5-(3 t)/(3))/(2 t/2) Cancel common terms in the numerator and denominator of (2 t)/2. (2 t)/2 = 2/2×t = t: ((2 t)/5-(3 t)/(3))/(t) Divide 3 by 3. 3/3 = (3×1)/3 = 1: ((2 t)/5-t)/(t) Put each term in (2 t)/5-t over the common denominator 5: (2 t)/5-t = (2 t)/5-(5 t)/5: ((2 t)/5-(5 t)/5)/(t) Combine (2 t)/5-(5 t)/5 into a single fraction. (2 t)/5-(5 t)/5 = (2 t-5 t)/5: ((2 t-5 t)/5)/(t) Combine like terms in 2 t-5 t. 2 t-5 t = -3 t: -3 t/(5 t) Combine products of like terms. (-3 t)/(5 t) = (-3 t^(1-1))/5: (-3 t^(1-1))/5 Look for two terms that sum to zero. 1-1 = 0: (-3 t^0)/5 Any nonzero expression to the zero power is one. t^0 = 1: Answer:(-3)/5
@DUDE..IM..A..DUCK Haha
Oh great I had this one right , Thank you @ybarrap
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