HELP PLEASE!
What are the x-coordinates of the solutions to this system of equations?
x2 + y2 = 16
y = x + 4
A. -4 and 0
B. 4 and 0
C. -2 and -3
D. 2 and -3
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OpenStudy (anonymous):
@tHe_FiZiCx99 @amistre64 ?
OpenStudy (amistre64):
we have a circle and a line ....
OpenStudy (amistre64):
let y = x+4 in the circle and you create the usual quadratic expression to play with
OpenStudy (anonymous):
a little lost :( I'm sorry
OpenStudy (amistre64):
x2 + y2 = 16 ; this is a circle, at least an equation of one
y = x + 4 ; this has to hold for y in any equation in the system, replace it in the circle
x2 + (x+4)2 = 16
expand it out and you create a quadratic: ax^2 + bx + c = k, which has plenty of methods to find a solution.
OR, just trial and error the options to see what fits
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OpenStudy (anonymous):
:l
OpenStudy (anonymous):
I just don't understand any of this
OpenStudy (amistre64):
x2 + (x+4)2 = 16
use this to test the options
Does x=0 work?
Does x=4 work?
Does x=-4 work?
etc ....
OpenStudy (anonymous):
x=4 works right? :D
OpenStudy (anonymous):
@amistre64
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OpenStudy (anonymous):
would it be B?
OpenStudy (anonymous):
@Mertsj Can you help?
OpenStudy (mertsj):
In the first equation, replace y with x+4
OpenStudy (mertsj):
Now you have only one variable. Solve the equation for x. You should get 2 answers and those are the answers to the question the problem asks.
OpenStudy (anonymous):
okay, can you hang around to make sure I'm right?
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OpenStudy (mertsj):
yes
OpenStudy (anonymous):
Thanks!
OpenStudy (anonymous):
how do I figure out what x^2 is?
OpenStudy (mertsj):
by solving that equation.
x^2+(x+4)^2=16
OpenStudy (anonymous):
this is what i have so far after solving for (x+4)^2
x^2 + 8 = 16
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OpenStudy (anonymous):
is that good so far?
OpenStudy (mertsj):
(x+4)(x+4)=x^2+8x+16
OpenStudy (anonymous):
combine like terms next?
OpenStudy (mertsj):
yes and get the equation equal to 0 by subtracting 16 from both sides.
OpenStudy (anonymous):
so when i combine like terms does it look like this? 8x^2 = 16
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OpenStudy (anonymous):
I think i did something wrong...?
OpenStudy (mertsj):
What is x^2+x^2?
OpenStudy (anonymous):
2x^2?
OpenStudy (mertsj):
Do you know that only like terms can be added?
OpenStudy (anonymous):
yes, I do
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OpenStudy (anonymous):
So, what do I do?
OpenStudy (mertsj):
Add the like terms
OpenStudy (mertsj):
How did you get 8x^2 if you know that only like terms can be added?
OpenStudy (anonymous):
I read it wrong. hold on
OpenStudy (anonymous):
I keep confusing myself :l
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OpenStudy (mertsj):
Here is what you should have:
x^2+(x+4)^2=16
x^2+x^2+8x+16=16
OpenStudy (mertsj):
Now: Add the like terms!!!
OpenStudy (anonymous):
12x + 16 = 16 is what I have so far
OpenStudy (anonymous):
wait!
OpenStudy (mertsj):
Do you know what like terms are?
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OpenStudy (anonymous):
x^2, x^2 and 8x are all like terms
OpenStudy (anonymous):
correct?
OpenStudy (mertsj):
Like terms are terms that have the same variables and those variables have the same exponents
OpenStudy (anonymous):
so x^2 and x^2 are like terms
OpenStudy (mertsj):
yes
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OpenStudy (anonymous):
when combined i get 2x^4?
OpenStudy (mertsj):
No. 1 cat + 1 cat is 2 cats
And 1x^2+1x^2 is 2x^2
OpenStudy (anonymous):
oh, i thought you had to combine the exponents too
OpenStudy (mertsj):
Did you skip Algebra I or something?
OpenStudy (anonymous):
Its been awhile....i did that freshmen year and now im a senior
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OpenStudy (anonymous):
I don't retain math very well as you can see...
OpenStudy (anonymous):
I think I'll just figure it out on my own...
OpenStudy (mertsj):
So now you have 2x^2+8x+16=16 right?
OpenStudy (anonymous):
yes
OpenStudy (mertsj):
Subtract 16 from both sides.
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OpenStudy (anonymous):
so now I combine 16 with 16 correct?
OpenStudy (anonymous):
okay
OpenStudy (anonymous):
now i have 2x^2 + 8x = 0
OpenStudy (mertsj):
Now divide both sides by 2
OpenStudy (anonymous):
x^2 + 4x = 0
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OpenStudy (mertsj):
Now factor out x
OpenStudy (anonymous):
4x^2?
OpenStudy (mertsj):
x^2+4x=x(x+4)
OpenStudy (mertsj):
Now set each factor equal to 0 and solve each equation.
OpenStudy (anonymous):
so it would be B?
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