Question

Which system of equations is represented by the graph? (2 points)
y = x2 - 6x - 7
x - y = 1
y = x2 - 6x + 7
x + y = -1
y = x2 + 6x - 7
x - y = 1
y = x2 + 6x + 7
x + y = 1

Answer 1

Well you could find out where the graphs cross the x axis and y axis by plugging zero in for x and y

Answer 2

Plug those values in that are given on your graph

Answer 3

can you identify the vertex, x-intercepts, and y-intercept of the parabola?

Answer 4

the choices of the parabola are not in vertex-form, but at least by asking this it tells me if you know anything about parabola at all

Answer 5

i really dont know much about this at all iv pretty much given up on the lesson for tonight seeing as its 11 and im tired from working all day this is due tonight so any explanation will be help full, sorry OS is being buggy

Answer 6

points (-6,7) and (-1,2)
eqn for parabola ax^2 +bx +c + 0 eqn for line y=mx + b

2= m(-1) + b
7 = m(-6)+ b
5= -5m
-1 =m
y = -x + 1
rewrite x + y = 1
from the answers only one with x + y = 1

Answer 7

i think i kind of get it so like raff said find out where the graphs cross the x axis and y axis by plugging zero in for x and y

Answer 8

solve for the parabola
check back tomorrow then i will still do to check solution

Answer 9

kk ty

Answer 10

you do not necessarily need to solve for the x-axis nor y-axis

Answer 11

you can start with three facts
fact 1: your line crosses the points (-6, 7) and (-1, 2)
from this information, you can solve for the slope, and then apply the point-slope form y-y1 = m(x-x1) to get to the slope-intercept form y = mx + b

fact 2: your parabola has a vertex of (-3.5, -2)
fact 3: your parabola has x-intercepts of [(-5, 0) and (2, 0)] and y-intercept of (0,7)

http://www.csun.edu/~ayk38384/notes/mod11/Parabolas.html

you are not solving for intercepts, because they are already visible in the graph