Question

Solve for x logarithms:

log 9 ^5√27=x
3

Answer 1

Clever way to write a subscript. :)

Answer 2

Have you learned the log rules? If you are multiplying within a log, it's the same as adding the logs of the two.

Answer 3

30sqrt(3) ?

Answer 4

is that 9^5(sqrt^27) in the question?

Answer 5

the log is included everything under the words

Answer 6

It's log base 3 of (9^5 x sqrt27) I think.

Answer 7

Use the multiplication/addition log rule! Then it's easy from there. Do you know of it?

Answer 8

no the 5 is over the square root sign like ^5√

Answer 9

no what is it

Answer 10

It's the fifth root?

Answer 11

Comme ca?

Answer 12

yes thats it

Answer 13

Then you apply the log rule I sent an example of before.

Answer 14

Tell me what you get after doing that and if you're still unable to solve it then I'll continue.

Answer 15

help please

Answer 16

Ah, the image is way complicated. Wait a moment.

Answer 17

simplify the 9*(27)^1/5

unfortunately doesn't show well w/o equation editor:

9*(27)^1/5 = 3^2*(3^3)^1/5

Answer 18

= 3^(2 + 3/5) = 3^(13/5)

Answer 19

It says solve for 'X'. So I did log base 3 9+1/5 log base 3 27=x
then power rule 2+1/5(3)=X
2.6=x
Am I on the right track ? KinzaN your thoughts?

Answer 20

Ah, you are. There was no need to bring the 1/5 down though. :)

Answer 21

27^(1/5) can be changed to 3 to some exponent.

Answer 22

13/5 = 2.6, so yes.

Answer 23

is ( 5sqrt27) the power to which 9 is raised?
9 = 3^2 and 27 =3^3
from log rule 3^x = 9 ^5√27

Answer 24

You can check that link triciaal

Answer 25

thanks now i can see the problem

Answer 26

wio?

Answer 27

Your answer has already been given, if that's what you're looking for. :)

Answer 28

I don't know what wio means
once i was able to see the problem I saw the correct answer was already given

Answer 29

Still haven't figured it out? =(