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Mathematics 18 Online
OpenStudy (danielbarriosr1):

Help me graphing please

OpenStudy (danielbarriosr1):

-2x+y>=3

OpenStudy (danielbarriosr1):

@mathmale

OpenStudy (danielbarriosr1):

Someone please

OpenStudy (mathmale):

Dan: Isolate y in -2x+y>=3 by adding 2x to both sides. Please type your result.

OpenStudy (danielbarriosr1):

y=2x+3

OpenStudy (danielbarriosr1):

y<=3x+3

OpenStudy (danielbarriosr1):

the sign switch right?

OpenStudy (mathmale):

Great, except that it's y "is equal to or greater than" 2x+3. No sign switch here. Your y was already positive. That's what we want. We got rid of 2x on the left side and thus isolated y, right?

OpenStudy (danielbarriosr1):

yes

OpenStudy (mathmale):

OK. Next, we need to graph y=2x+3. Notice that I've omitted the > symbol for the present. Are you readily able to graph y=2x+3, or do you need some review? If you can graph it yourself, please go ahead.

OpenStudy (texaschic101):

we need to put this in y = mx + b form -2x + y >= 3 --- add 2x to both sides y >= 2x + 3 In y = mx + b form, the m is the slope and the b is the y intercept. slope = 2 y intercept = (0,3) To find the x intercept, sub in 0 for y -2x + y = 3 -2x + 0 = 3 -2x = 3 x = -3/2 (x intercept is (-3/2,0) for graphing purposes, -3/2 = -1 1/2 so plot your intercepts (0,3) and (-3/2,0) you can also start at the x intercept (-3/2,0) and since the slope is 2, go up 2 (because it is positive) and to the right 1, and up 2, and to the right 1, and you should cross the y axis at (0,3) It will be a solid line because there is an equal sign. It will be shaded above the line because y is >= (greater then or equal)

OpenStudy (danielbarriosr1):

Ok i wll do it

OpenStudy (danielbarriosr1):

Done

OpenStudy (danielbarriosr1):

@mathmale

OpenStudy (danielbarriosr1):

Now?

OpenStudy (danielbarriosr1):

Please @mathmale

OpenStudy (mathmale):

Sorry for the delay, Daniel. Where are you now in the solution of this problem? Were you able to follow all of texaschik's instructions, and, if so, do you have the graph completed?

OpenStudy (danielbarriosr1):

No, i didnt get it

OpenStudy (danielbarriosr1):

I just have the Line in the graph

OpenStudy (mathmale):

daniel, to be honest with you, I'm involved in helping another student at the moment, but I promise to get back to you. Perhaps you could take a break or consider how to solve the next problem on your list. C u shortly. MM

OpenStudy (danielbarriosr1):

ok

OpenStudy (mathmale):

We're graphing y=2x+3. Are you satisfied that you've graphed that correctly?

OpenStudy (danielbarriosr1):

yes

OpenStudy (mathmale):

Good. The original problem statement asks you to graph the inequality -2x+y>=3. You already have a graph for -2x+y=3. Now consider the inequality -2x+y>3. Pick any point at random from your cartesian plane that is NOT on the line you've drawn. Type it back to me in the form (x,y).

OpenStudy (danielbarriosr1):

(1,1)

OpenStudy (mathmale):

So you've chosen x=1 and y=1. Great. Would you please substitute those values into the inequality -2x+y>3 and determine whether or not the inequality is now true.

OpenStudy (mathmale):

Here's what I meant: if x=1 and y=1, then -2x+y>3 becomes -2(1)+(1)>3 and your task is to determine whether or not that inequality is true.

OpenStudy (danielbarriosr1):

-1>=3 No

OpenStudy (danielbarriosr1):

so it isnt true right

OpenStudy (mathmale):

Dan, if your inequality is false, this is an indication that you need to shade the OTHER side of the graph. Do that, and you'll be done. Or, if you'd like to udnerstand this process better, choose a point from the other side of the graph and test the inequality in the same way. If it is now true, that means that you've chosen a point from the "right" / "correct" side of the line to shade.

OpenStudy (mathmale):

You've done nothing wrong. You found that the inequality wasn't true, which indicates that you need to shade the other side of the line. That's it.

OpenStudy (danielbarriosr1):

Ok. Now i got it

OpenStudy (mathmale):

I'm really happy for you. Thank you for sticking with this problem and with me all the way through.

OpenStudy (danielbarriosr1):

Thanks to you

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