Question

6a^-1c^-3 / d^0

Answer 1

@shamil98

Answer 2

d^0=1

Answer 3

I think its, 6a^-1 * c^-3 / d^0

1/6^1 * 1/c^3 / 1

Answer 4

I'm so lost, i need Shamil. He's offline. :(

Answer 5

6a^-1 = 1/6a, c^-3 = 1/c^3, d^0 = 1

Answer 6

Basically what I put lol

Answer 7

I just saw it lol sorry ello

Answer 8

:3 np

Answer 9

Uhg equation and draw is still broken :c

Answer 10

Shawty x^-1 = 1/x

Answer 11

Are you getting this?

Answer 12

I have like 3 different people telling me different things. :(

Answer 13

It's all the same lol

Answer 14

ex) x^-6 = 1/x^6

Answer 15

6a^-1c^-3 / d^0 =

1/6a*c^3

Answer 16

\[\frac{ 6a ^{-1} \times c ^{-3} }{ d ^{^{0}} } = \frac{ \frac{ 1 }{ 6a ^{1} } \times \frac{ 1 }{ c ^{3}} }{ 1 }\]

Answer 17

sorry it should be 6/a*c^3

Answer 18

can you look at my problem batman? LOL that sounded weird >.>

Answer 19

It's all the same thing m8, just different ways of putting it.

Answer 20

can i tag u?

Answer 21

in?

Answer 22

my prob

Answer 23

Sure, I don't guarantee I'll be able to solve it though!

Answer 24

Hope you understand storm :X

Answer 25

6a^-1c^-3 / d^0
anything to the power of zero is 1. (excluding zero i think ).
Let's break this up into parts to better understand it.
6a^-1c^-3 / d^0

6 * a^-1 * c^-3 / d^0
6 * a^-1 * c^-3 / 1
dividing by 1 just gives that value/term/number so it stays the same.
remember x^-n = 1/x^n
so

6 * a^-1 * c^-3
6 * 1/a* 1/c^3

6/a * 1/c^3

6/ac^3

Answer 26

oh sorry for the late explanation, still working on my essay..

Answer 27

Yo sham

Answer 28

hai bat