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Mathematics 16 Online
OpenStudy (anonymous):

Estimating Square Roots need help A.S.A.P

OpenStudy (solomonzelman):

you calculate the root using a calculator and round it up.

OpenStudy (anonymous):

\[\sqrt{175}\] let 10.5 be you initial guess \[\frac{ 13.5+\frac{ 170 }{ ? } }{ 2 }\approx13.0463\]

OpenStudy (anonymous):

i

OpenStudy (solomonzelman):

you don't need to guess, can't you use a calculator (if you are NOT asked to find the exact value of it) ? \[Calculator: ~~~~~~~~~~\sqrt{175}=13.22875655532295≈13.23\]

OpenStudy (anonymous):

A.13.5 B.12.6 C.175 D.2

OpenStudy (anonymous):

Fill in the missing information in the problem to find \[\sqrt{175}\] by using the Babylonian method. Let 10.5 be your initial guess.

OpenStudy (solomonzelman):

Oh, I never used that method, idk.

OpenStudy (anonymous):

hey

OpenStudy (anonymous):

@random777

OpenStudy (anonymous):

A.13.5 B.12.6 C.175 D.2

OpenStudy (anonymous):

hi @amistre64

OpenStudy (anonymous):

can either one yall help me?

OpenStudy (amistre64):

make a guess: 10.5 divide the original number by that guess: 175/10.5 find the average: (175 + 175/10.5)/2 that is your new guess ..................................................... the sqrt(n) ... (n + n/g)/2 = g1 (n + n/g1)/2 = g2 (n + n/g2)/2 = g3 eyc ....

OpenStudy (anonymous):

i still dont get it

OpenStudy (amistre64):

seems like i messed up a little, you take the average of your "guesses"

OpenStudy (amistre64):

\[g_n=\frac{[g_{n-1}]^2+n}{2g_{n-1}}\] sooo \[g_n=\frac{[10.5]^2+175}{2(10.5)}\] \[13.58333=\frac{[10.5]^2+175}{2(10.5)}\]

OpenStudy (anonymous):

so the answer is A?

OpenStudy (anonymous):

A.13.5 B.12.6 C.175 D.2

OpenStudy (amistre64):

yes, ideally it is 13 point 'something' so A seems to fit pretty good

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

can you give me a medal

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