Question

help medal will be given!!!!!!
for a 225-watt bulb, the intensity i of light of humens at a distance of x feet is i=225/x^2 A.what is the intensity of light 5ft from the bulb B. suppose your distance from the bulb doubles, how does the intensity of the light change ? explain

Answer 1

a)

l(5) = 225/5^2 = 9

b)

Intensity decreases by a factor of 2^2 = 4.
So intensity will be 1/4 what it was before distance was doubled

Let d = original distance from bulb. Then we get intensity
l = 225/d^2

If we double distance (to 2d) we get intensity
l = 225/(2d)^2 = 225/(4d^2) = 1/4 (225/d^2) = 1/4 * original intensity

Answer 2

Hey doll, this guys is right, everything checks out!