find the horizontal or oblique asymptote of f(x)
@dumbcow
@dumbsearch2 @Ashleyisakitty
@Fifciol @radar @Grama-Pimpsta
We know it's an oblique asymptote because the function in the numerator has a higher degree than the denominator (ie. x^2 versus just x).
You then have to divide the numerator by the denominator using either long division or synthetic division (whichever one works best for you), and the function you have left if your oblique asymptote. (:
hmm ok lemme try i guess
yeahh idk which to divide
Have you learned how to divide polynomials?
im not clear on it
ok so where to put the x+2
In synthetic division, you divide by the opposite of the variable. So instead of placing '2' into the division square, you write '-2'
so..-2 / -2,3,6?
Yes, and then continue on. The new numbers you get on the bottom are your new coefficients for the oblique asymptote.
Ok I got -2,7,-8
Right, so your oblique asymptote would be y= -2x^2+7x-8
thanks :)
No problem, glad I could help.
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