Ask your own question, for FREE!
Mathematics 14 Online
OpenStudy (anonymous):

find the horizontal or oblique asymptote of f(x)

OpenStudy (anonymous):

OpenStudy (anonymous):

@dumbcow

OpenStudy (anonymous):

@dumbsearch2 @Ashleyisakitty

OpenStudy (anonymous):

@Fifciol @radar @Grama-Pimpsta

OpenStudy (anonymous):

We know it's an oblique asymptote because the function in the numerator has a higher degree than the denominator (ie. x^2 versus just x).

OpenStudy (anonymous):

You then have to divide the numerator by the denominator using either long division or synthetic division (whichever one works best for you), and the function you have left if your oblique asymptote. (:

OpenStudy (anonymous):

hmm ok lemme try i guess

OpenStudy (anonymous):

yeahh idk which to divide

OpenStudy (anonymous):

Have you learned how to divide polynomials?

OpenStudy (anonymous):

im not clear on it

OpenStudy (anonymous):

Check this out: http://www.purplemath.com/modules/synthdiv.htm

OpenStudy (anonymous):

ok so where to put the x+2

OpenStudy (anonymous):

In synthetic division, you divide by the opposite of the variable. So instead of placing '2' into the division square, you write '-2'

OpenStudy (anonymous):

so..-2 / -2,3,6?

OpenStudy (anonymous):

http://prntscr.com/2n4utx

OpenStudy (anonymous):

Yes, and then continue on. The new numbers you get on the bottom are your new coefficients for the oblique asymptote.

OpenStudy (anonymous):

Ok I got -2,7,-8

OpenStudy (anonymous):

Right, so your oblique asymptote would be y= -2x^2+7x-8

OpenStudy (anonymous):

thanks :)

OpenStudy (anonymous):

No problem, glad I could help.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!