Question

Simplify the sum. State any restrictions on the variables.
2/3 + 10x/x^2-9

Answer 1

@superdavesuper

Answer 2

Oh crap - this is really making it difficult to read....is ur Q: 2/3 + 10x/(x^2-9) right? Or there is no bracket and the 9 is outside the division?

Answer 3

\[\frac{ x-2 }{ x+3 }+\frac{ 10x }{ x ^{2}- 9}\]

Answer 4

unfortunately LaTex is not working :(

Let me see if I can type it out with brackets:

[(x-2)/(x+3)] + [10x/(x^2-9)]

is that right?

Answer 5

yes

Answer 6

@superdavesuper

Answer 7

sorry stuck in updating OS :(

OK to simplify this, plz note x^2-a^2=(x+a)(x-a)
so can u do the same for x^2-9?

Answer 8

i don't think so.. i dont really get it

Answer 9

(x^2-9) is in the bottom of ur Q right? so u need to group it and I gave the eqn to group it in my last post....

x^2-9=x^2-3^2=???