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Simplify the sum. State any restrictions on the variables. 2/3 + 10x/x^2-9
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@superdavesuper
Oh crap - this is really making it difficult to read....is ur Q: 2/3 + 10x/(x^2-9) right? Or there is no bracket and the 9 is outside the division?
\[\frac{ x-2 }{ x+3 }+\frac{ 10x }{ x ^{2}- 9}\]
unfortunately LaTex is not working :( Let me see if I can type it out with brackets: [(x-2)/(x+3)] + [10x/(x^2-9)] is that right?
yes
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@superdavesuper
sorry stuck in updating OS :( OK to simplify this, plz note x^2-a^2=(x+a)(x-a) so can u do the same for x^2-9?
i don't think so.. i dont really get it
(x^2-9) is in the bottom of ur Q right? so u need to group it and I gave the eqn to group it in my last post.... x^2-9=x^2-3^2=???
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