Find the derivative of the function using the definition of derivative.
f(x)= 3+x/1-3x
@phi
how far did you get ?
I cross multiplied the top @phi
3+(x+h)/1-3(x+h) - 3+x/1-3x ------------------------- h
ignoring the divide by h for the moment, you have two fractions. Put them over a common denominator of (1-3x-3h)(1-3x)
that means multiply the first fraction by (1-3x)/(1-3x) and multiply the second fraction by (1-3x-3h)/(1-3x-3h)
wait let me get in the same pic as you
before I do that step, do I simplify the parentheses ?
for ex: 1-3(x+h)?
you could distribute everything, and get lots of terms (of which most will cancel) or in the first fraction you can write (3+(x+h)) as (3+x) + h multiply it by (1-3x) to get (3+x)(1-3x) + h(1-3x) do the same for the second fraction, write 1-3(x+h) as (1-3x) - 3h -(3+x)( (1-3x) - 3h )= -(3+x)(1-3x) + 3h(3+x)
the top will be (3+x)(1-3x) + h(1-3x) -(3+x)(1-3x) + 3h(3+x) notice that (3+x)(1-3x) - (3+x)(1-3x) = 0 so you get h(1-3x)+ 3h(3+x) now distribute the h (and 3h) to get h -3hx +9h +3hx which simplifies
Took me a while to process all that. All right, i got it!
so its going to be h-3hx+9h+3hx/ (1-3x)-3h
@phi
or is the answer just 9?
It's 9.
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