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Mathematics 13 Online
OpenStudy (anonymous):

Find the derivative of the function using the definition of derivative.

OpenStudy (anonymous):

f(x)= 3+x/1-3x

OpenStudy (anonymous):

@phi

OpenStudy (phi):

how far did you get ?

OpenStudy (anonymous):

I cross multiplied the top @phi

OpenStudy (anonymous):

3+(x+h)/1-3(x+h) - 3+x/1-3x ------------------------- h

OpenStudy (phi):

ignoring the divide by h for the moment, you have two fractions. Put them over a common denominator of (1-3x-3h)(1-3x)

OpenStudy (phi):

that means multiply the first fraction by (1-3x)/(1-3x) and multiply the second fraction by (1-3x-3h)/(1-3x-3h)

OpenStudy (anonymous):

wait let me get in the same pic as you

OpenStudy (anonymous):

before I do that step, do I simplify the parentheses ?

OpenStudy (anonymous):

for ex: 1-3(x+h)?

OpenStudy (phi):

you could distribute everything, and get lots of terms (of which most will cancel) or in the first fraction you can write (3+(x+h)) as (3+x) + h multiply it by (1-3x) to get (3+x)(1-3x) + h(1-3x) do the same for the second fraction, write 1-3(x+h) as (1-3x) - 3h -(3+x)( (1-3x) - 3h )= -(3+x)(1-3x) + 3h(3+x)

OpenStudy (phi):

the top will be (3+x)(1-3x) + h(1-3x) -(3+x)(1-3x) + 3h(3+x) notice that (3+x)(1-3x) - (3+x)(1-3x) = 0 so you get h(1-3x)+ 3h(3+x) now distribute the h (and 3h) to get h -3hx +9h +3hx which simplifies

OpenStudy (anonymous):

Took me a while to process all that. All right, i got it!

OpenStudy (anonymous):

so its going to be h-3hx+9h+3hx/ (1-3x)-3h

OpenStudy (anonymous):

@phi

OpenStudy (anonymous):

or is the answer just 9?

OpenStudy (anonymous):

It's 9.

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