Question

Write the equation of the line which passes through (-4, 3) and with slope of 1 in slope-intercept form.

y=x+3
3x−4y=1
y−3=x+4
y=x+7

Answer 1

slope intercept form : y = mx + b
slope(m) = 1
(-4,3) x = -4 and y = 3
now we sub and find b
3 = 1(-4) + b
3 = -4 + b
3 + 4 = b
7 = b
so your equation is : y = x + 7

Answer 2

any questions ?

Answer 3

i have one last problem like this i need help with, could you help me with it ?

Answer 4

sure...what ya got ?

Answer 5

Write the equation of the line which passes through (5, -2) and (3, 4) in standard form.

Answer 6

ok...first we need to find the slope by using the slope formula.
slope(m) = (y2 - y1) / (x2 - x1)
(5,-2) x1 = 5 and y1 = -2
(3,4) x2 = 3 and y2 = 4
now we sub
slope(m) = (4 - (-2) / (3 - 5)
slope(m) = (4 + 2) / -2
slope(m) = 6/-2 which = - 3

now we will use y = mx + b and solve for b
slope(m) = -3
you can use either of your set of points
(3,4) x = 3 and y = 4
now we sub
4 = -3(3) + b
4 = -9 + b
4 + 9 = b
13 = b
equation is : y = -3x + 13
However, we need it in standard form Ax + By = C

y = -3x + 13 --- add 3x to both sides
3x + y = 13 ====> standard form equation

Answer 7

any questions ?

Answer 8

nope! thanks so much!!!

Answer 9

anytime :)