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Help with simplifying logarithm? =)
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oo logs are fun :)
As we take 9 out, we have logx - log y, which using identity is log (x/y) we also know that log x^2 = 2log x therefore 9log (x/y) = log (x/y)^9 All the best :)
Hi, Cat Lover, I'm one myself. There are 3 basic rules for logs applying to problems such as this one. One states: ln x + ln y = ln (xy). Can you write out the other two? Please look them up if need be.
Note that Mathbreaker has already applied the two rules I've asked you to write out. Thanks very much for the medals.
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