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Mathematics 17 Online
OpenStudy (anonymous):

Help with simplifying logarithm? =)

OpenStudy (anonymous):

zepdrix (zepdrix):

oo logs are fun :)

OpenStudy (anonymous):

As we take 9 out, we have logx - log y, which using identity is log (x/y) we also know that log x^2 = 2log x therefore 9log (x/y) = log (x/y)^9 All the best :)

OpenStudy (mathmale):

Hi, Cat Lover, I'm one myself. There are 3 basic rules for logs applying to problems such as this one. One states: ln x + ln y = ln (xy). Can you write out the other two? Please look them up if need be.

OpenStudy (mathmale):

Note that Mathbreaker has already applied the two rules I've asked you to write out. Thanks very much for the medals.

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