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What are the coordinates of the vertex of y = x^2 - 4x - 5? (2, -9) (2, -5) (-2, 7) (-2, -5)
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y=−2x−5
-2, -5 :) Please give a medal
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No problem. :D
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i think it is a good thing to show your work and also don't you need to complete the square then turn into vertex form
What? @helpme1.2 ???
vertex form: y = a(x-h)^2+k y = x^2 - 4x - 5 y = (x^2-4x +4)-5-4 y = (x-2)^2-9 now that is in vertex form which means the coordinates would be (2,9)
(2 -9)*
does this make sense @Nikkeyiboo ?
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