Image.
*Never mind. The x intercepts were right, but not the y-intercept.
What are the functions provided?
cubic?
If you insist, A:-1/2(x-3)(x+2) B:1/6(x-3)^2(x+2) C:1/4(x+3)(x-2)^2 D:-1/4(x+3)(x-2)^2 E:1/2(x-3)^2(x+2)
We know it should be zero at -2 and 3.
So it has to have x+2 and x-3
When you set x=0, you should have some value near 3
Set x=1 then you have a value near 2
How would you do it if there were no answer choices?
Well, there are infinite solutions technically. You don't even know that it is a polynomial.
If they asked for an approximate equation?
One thing you could do is assume it is an n-degree polynomial and set up a matrix
suppose it was degree 5 Then we have: y = ax^5 + bx^4 + cx^3 + dx^2+ ex + f
Given 5 different points (x,y), we could come up with 5 equations.
Then it just because a matrix solving for the coefficients.
Okay.
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