Question

Here is a new problem from http://saab.org
I attached the wrong file in my previous problem.

Answer 1

can you use a calculator for this problem? if so,
P(n>0 | n<9) = 1-P(n=0 | n<9) = 1-P(n=0)/P(n<9)

Answer 2

Of course, you can use a calculator

Answer 3

Probability of at least one claim (n>0) is one minus the probability of no claims , (n=0). Simplifies your life.

Answer 4

Did you get an answer?

Answer 5

\[\sum_{n = 0}^{8} \frac{4}{(n+4) (n+5)}\]
\[\sum_{n = 0}^{8} \frac{4}{(n+4) (n+5)} = \frac{4}{20}+\frac{4}{30}+\frac{4}{48}+\frac{4}{56}+\frac{4}{72}+\frac{4}{90}+\frac{4}{110}+\frac{4}{132}+\frac{4}{156}+\frac{4}{182} \approx 0.70\]

Answer 6

B. 0.70

Answer 7

It is C

Answer 8

Sorry about that :-P. This is new stuff to me.

Answer 9

@Opcode , one has to try and not give up.

Answer 10

Wise words :-).