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OpenStudy (anonymous):
What is a possible formula for the graph attached inside? :)
f(x)=_________
thanks :)
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OpenStudy (anonymous):
graph :)
OpenStudy (agent0smith):
Notice it's shifted up 3,
and the period is 6
and the amplitude is 3
Follow the last question, see if you can work out the formula.
OpenStudy (anonymous):
okay... umm
f(x)=AsinBt+C ?
so f(x)=-3sin+(2pi/6) + 3 ?
and simplifies to f(x) = -3sin + 1/3pi + 3 ? :/
OpenStudy (anonymous):
i think i forgot something...
should it be 1/3pi x ?
or t? :/
OpenStudy (agent0smith):
Amplitude is just 3 this time.
B = 2pi/T where T is period
And it's sinBt not sin+Bt :P
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OpenStudy (anonymous):
oh oops!
and there's no +C here is there?
OpenStudy (anonymous):
so f(x)=AsinBt ?
OpenStudy (agent0smith):
Follow the last question haha :P C is the shift up
OpenStudy (anonymous):
right :P
okay
so f(x)=AsinBt+C
f(x)=3sin(2π/6) + 3
f(x)=3sin(π/3) + 3 ?
OpenStudy (agent0smith):
You're still missing t...
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OpenStudy (anonymous):
ohh :(
f(x)=3sin(pi/3)t+3 ?
OpenStudy (agent0smith):
Good :)
OpenStudy (anonymous):
yay!! :) thanks!! :)
OpenStudy (agent0smith):
good job :)
OpenStudy (anonymous):
hehe thank you!! :) i seriously need to remember the t though lol.. i keep forgetting it :P
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OpenStudy (agent0smith):
haha yes :) can't forget the variable
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