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Mathematics 13 Online
OpenStudy (anonymous):

Calculus

OpenStudy (anonymous):

zepdrix (zepdrix):

Were you able to determine that any of these ARE true? So we can start to eliminate some of our options.

OpenStudy (anonymous):

I don't think the last 2 are true

OpenStudy (anonymous):

have you done the work to prove that?

zepdrix (zepdrix):

If we factor the denominator, we can find out where the `vertical` asymptotes are located. 2x^5 - 2x Factoring a little bit gives us: 2x(x^4-1) Factoring a little bit more gives us: 2x(x^2-1)(x^2+1) and a little bit more... 2x(x-1)(x+1)(x^2+1) Each of these factors, when set equal to zero, tells us where our asymptotes are located. 2x = 0 --> x=0 is an asymptote. x=0 is the y-axis. So the last option IS true. ok?

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

so the second to last is not true?

OpenStudy (anonymous):

I have to get off the computer in 3 minutes :(

OpenStudy (anonymous):

@ganeshie8

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