Solve Initial Value Problem? dy/dx=y/x and y=2 when x=2
oooo differential equations? separable equations?
ok so we need x's on one side and y's on the other.. in the form of h(y) dy = f(x) dx
so multiply the y/x by dx and divide the y... this is so hard without draw!
Okay done
we need a y not a ln y so I think we need to e to the everything
my bad i didn't even see you typing.
WHAT THE HECK?
lol :P
I thought antiderivative of 1/y 1/x is ln y and ln x? :P
ufkodfjdskfdslj;sdaf ljdfslkj I have to finish my latex or I'm screwed...
i did dy/dx = x/y good thing you're here :P
yeah but we need the equation in the form of h(y) dy = f(x) dx
Well now I'm confused
:o
so ... dx needs to go to the right the y oh wait. ugh that could be me screwing it up by accident... it would be let me redraw this.
Equation and draw tool are still broken :c le sigh...
yeah I effed up by accident sorry long day at school tired D:
Ooo neat tool :O Never seen this before!
Why x/y ?
there whew..........
this is a separable equation... please go to the link for the drawing of your problem
you need all y's to the left and all x's to the right
The original problem was y/x silly D:
OMG just see my drawing D:<
But..... :(
You started with dy/dx = x/y the original problem is dy/dx = y/x .... :C
ughhhhh sorry my bad...oh man second time fine third time is the charm as they say
XD
Why is the cutting of the bottom quarter of the page on twiddla? Am I the only one having that problem? :[ Hmm weird..
****** I was right earlier with the lns who is trying to screw me up ? D:
Sigh...
Yes you were on the right track the first time it appears :o
yeah someone threw me off. >:/
@Euler271 DID IT >:O
And now I'm stealing your thunder XD Sneaky green text lol
change to (1/y) dy/dx = (1/x) Then integrate both sides with respect to x.
This twiddla is way cool. Imma have to use this til we get our site utilities up and working.
So zepdrix your answer is correct?
I think so :o It got erased t.t pony got mad
I wrote it all down
Did you understand the exponentiation step she was doing? :o That part can be a little tricky.
Particularly, did you understand why the C is now being multiplied instead of added?
exponential rules
Yeah, I got it:) Thanks for the help. Phew. I need some sleep :P
Join our real-time social learning platform and learn together with your friends!