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what does sin^2t =? In relation to trigonometric functions.
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Supposedly it equals 1-cos2t/2 but I don't understand why.
oh it's just a trig identity i think.
yes it is...do u know cos(A+B)=cosAcosB-sinAsinB? u will need to use that...
yeah Sin(A+B) = SinACosB + CosASinB
so cos2t=cos(t+t)=....?
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You will use here the double angle identity. Wherein cos2t = 1-2sin^2 t Hence, 2sin^2 = 1 - cos^2 t hence sin^2 t = (1 - cos^2 t)/2
super it would be cosTcosY - sinTsinY
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