Ask your own question, for FREE!
Physics 21 Online
OpenStudy (anonymous):

In the figure Q =4.6 nC and all other quantities are exact. What is the magnitude of the force on the charge Q?

OpenStudy (anonymous):

OpenStudy (anonymous):

do u know coulombs law?

OpenStudy (anonymous):

and the superposition principle?

OpenStudy (anonymous):

i know coulombs law

OpenStudy (anonymous):

fine....then do u know that Force on any charge at any point in space is electric field at that point times the charge u want to keep.

OpenStudy (anonymous):

k, then find the electric field at the vertex(where Q is kept) ,, due to the other charges

OpenStudy (anonymous):

get it?

OpenStudy (anonymous):

well I'm working on it but I'm confused:S

OpenStudy (anonymous):

ok.....first find electric field at the point due to charge on the left end alone....

OpenStudy (anonymous):

K Q/ r^2

OpenStudy (anonymous):

i got 162.286x10^-5 for the final asnwer ????:S

OpenStudy (anonymous):

N for the unit.s

OpenStudy (anonymous):

wait fora moment...lemme calculate

OpenStudy (anonymous):

ok .s

OpenStudy (anonymous):

i think its 1.434096 X 10^-3

OpenStudy (anonymous):

what did u do ? method?

OpenStudy (anonymous):

its only this....horizontal components of the fields(forces) cancel out .....vertical components add up....to find the vertical components u need geometry....Fcos(theta),,,,where theta is the angle between the electric field and the vertical

OpenStudy (anonymous):

well i found Force by each charge then found F(net)

OpenStudy (anonymous):

no thats not possible.......u have forgotten that forces are indeed vectors.....and vectors dont add up by normal method a+b.....u must apply vector algebra

OpenStudy (anonymous):

ur method is possible only if both the forces are in the same direction

OpenStudy (anonymous):

but they are not!

OpenStudy (anonymous):

get it?

OpenStudy (anonymous):

yes thnk u.d

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!