Please answer! *Will give medal!*

Which of the following probability tools would not be a reasonable choice to model the likelihood that Zoe will get a grape gumball from a machine that has 6 different flavors: blue, cherry, grape, lemon, lime, and orange?

A) Die
B)Spinner
D)Slips of paper

Question

Please answer! *Will give medal!* 

Which of the following probability tools would not be a reasonable choice to model the likelihood that Zoe will get a grape gumball from a machine that has 6 different flavors: blue, cherry, grape, lemon, lime, and orange? 

A) Die
B)Spinner
D)Slips of paper

***[isuru]*** · Answer

A die.. because the probability of the die is also same

anonymous · Answer

I would think a die is reasonable because the probability of the die is the same...It says which would NOT be reasonable.

***[isuru]*** · Answer

OPS!! i didn't c that one coming ..lol

anonymous · Answer

Do you have another answer maybe???....

***[isuru]*** · Answer

mmm im not sure but u may want to have a look at this one

openstudy.com/updates/51a49e99e4b0aa1ad887d525‎

***[isuru]*** · Answer

and what abt ur choice (C) ??? it's not here ?

anonymous · Answer

Honestly they all make sense to me. A spinner could have 6 segments all labeled by each flavor. A die have 6 sides. And you could have 6 papers with each of the names of the flavors and draw one randomly. Ugh I'm panicking this is a really important test.

anonymous · Answer

Because everyone keeps saying a coin and although that seems like the obvious answer that's wrong because you could use 6 coins or something.

***[isuru]*** · Answer

this is a blind shot....
     what would u do if there were more than one gumball from each flavor in that machine...
if there was 6 grape one and only one from the rest the probability of getting grape is higher... this difference can't be illustrate by a dice since it has only 6 sides... in a dice the probability of each side is same .... but both in slips of paper and the spinner u can model that difference 
what do u think ?

anonymous · Answer

No, I disagree with that because a coin only has 2 sides. And my friend had selected on her test that a coin was the most unreasonable and the result of that was incorrect This question is absolutely ridiculous

***[isuru]*** · Answer

but there r few more arguments...
    the first one is... 
            even though the above scenario happens there is only 1  result in the end..
        you GET the grape or U DON'T GET the grape... whatever happens that's a constant... so whatever happens a coin can represent that model and due to that it's always reasonable to use it..
        but if u consider a dice  u can't  represent that module in a dice ...  so if the above scenario happens a dice fails.
      also the probability of a dice is 1/6 and that of a coin is 1/2 and what ever happens u cant change those 2. But what ever the instance is u can use the coin under the probability U GET or U DON'T but the dice don;t have such a option

and there is one more...
       the coin is already revealed as a reasonable tool because u say that ur friend get it wrong by  choosing the coin as answer.. so out of the rest if u sort out the dice is the reasonable answer to me for this question 

:)