Can someone explain this Alg 2 question to me please?
Do you know what holes are?
no ideas
Look at the equation, what happens if x = -4?
it equals 0
Yes, the denominator equals 0 and what happens when you divide by 0?
Nothing happens it stays the same?
You cannot divide by 0. Try it on a calculator, it is not allowed. It is undefined and will produce an error, do you agree?
yes
This particular example has an exception since if you look at the bottom and look at the top of the fraction you'll notice that they both have (x+4) terms and they can cancel each other out, do you understand this?
so far yes
Here's the thing though, normally when you cancel out terms the value of the equation stays the same. The graph will look the same.
This is where, "holes" come in.
brb I have to reopen browser
ok back.
Now, do you agree that when you cancel out terms in a fraction that the value of the fraction will stay the same?
Yes
Exactly correct.... Most of the time!
If you cancelled out those terms in this equation, the shape of the equation will stay the same, but it will no longer be undefined when x = -4.
This is a very important concept to understand, this is what a "hole" in an equation is and where it comes from.
So the hole would be x=-4?
Exactly
Do you understand why though?
because it canceled out the term?
Yes. Because the function IS essentially equivalent to the function you will get when you cancel out those terms. The only difference is that the original function you have (before cancelling out the term) will be undefined when x = -4.
Following?
Yes surprisingly i am.
Do you understand asymptotes?
No /.\
It's not a surprise, you're a smart person. Everyone is smart, sometimes they just don't have the tools they need.
Do you know what an asymptote looks like on a graph?
Yes
Perfect, then I'll start from there. Consider the function you have given me. What happens when x = -1?
i see the same thing happens like last time the two terms cancel out
No. Stop.
This is a separate idea I'm talking about here I don't want you to relate them.
Remember the golden rule, "NEVER DIVIDE BY 0". When x = -1 here it will make the bottom of the fraction have a 0. So it will be undefined.
Still with me?
Ohhh so you just wanted me to plug in -1 all the way across? When i did that i got 3/0 but i also noted that the numerator and denomorator both had (-1+4) thats what i was talking about
Well I just want you to notice that when you plug -1 in the bottom you will get a 0 which is something to pay attention to. They are important in recognizing the characteristics of how a function behaves.
This term cannot be cancelled out. That's why it's different from the previous idea of a "hole".
Only the bottom has the term (x+1)
Ok im still following you.
:D That's what I like to hear.
Ok, now consider this. What happens when you divide by a number less than 1?
Something divided by a number between 0 and 1
This is the key to understanding asymptotes (well vertical asymptotes I should say)
The quotient is bigger than what you started with? Maybe thats worded weird idk >.<
No worries, I understand what you mean perfectly. That's exactly correct!
Now another thing to realize is the smaller the number you divide by, the larger the outcome
Try it out on a calculator. 17 / 0.5 and 17 / 0.00005
ok so 34 vs. 340000 :)
Now look at the function you gave me. You don't have to give me an exact answer, but try to guess what will happen when x = -0.9999999
It will get bigger?
It will get much bigger. In fact, the closer that x gets to being -1 the huger the value will be, agreed?
This is because as x approaches -1. x + 1 will be get a lot smaller.
And we know that dividing by a small number, makes our value bigger.
Do you understand this trend?
yes
That's why you see an asymptote on a graph shoot straight up or down. But do you know why it goes up on one side and down on the other?
Not really
Let's focus just on the term (x+1)
ok
What happens when x is a TINY bit smaller than -1? Will the value be positive or negative?
It will still be neg?
Nope, it will be positive. Think: (x+1) -0.9 + 1
= 0.1
Oh sorry i wasnt thinging right, but go on.
*thinking
Now what about when x is a TINY big "larger" than -1, I mean x = -1.000000001
What will the answer be? Positive or negative?
That would be negative.
It won't just be negative. It will be a very tiny negative number.
Now combine this with what we learned earlier about dividing by a small number, and you can figure out the rest. That's what an asymptote is. I want you to come up with the rest of the reasoning, I'm sure you're a smart person.
Please take a moment and try to explain it to me here and I will let you know.
I think i an do it from here
Explaining yourself is also a way to practice and improve your knowledge of something.
*can
Well, up to you. Good luck. I hope this helped.
It did so much thank you truly. :)
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