Question

Help me with this logarithm!

Answer 1

Log(3sqrt(5y))/(x^2) write as a sum or difference of logarithmic terms.

Answer 2

and that's a cube root!

Answer 3

log base 10 of [ cube root of 5y over x^2 ] ?

Answer 4

Yeah!

Answer 5

log (AB/C) = log A + log B - log C

Answer 6

use that property.. here are some other http://www.teachengineering.org/collection/van_/lessons/van_bmd_less2/log_properties_lesson2_fig2.jpg

Answer 7

then take the powers out the front

log D^n = nlog D

Answer 8

So I have...1/3log5y-logx^2

Answer 9

sqrt is the same a power 1/2, [not 1/3]

Answer 10

it was a cube root. I typed it wrong. it was Log(cube root(5y)/x^2)

Answer 11

oh ok

in that case

1/3log5y-logx^2 is good,

now you can take the 2 for the power of x out the front of that log,

Answer 12

and you can also split the first log into a sum

Answer 13

Okay! So would it be 1/3log5+1/3logy-2logx ?

Answer 14

YES! good show

Answer 15

Thanks!! :)