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Mathematics 8 Online
OpenStudy (anonymous):

calculus 2

OpenStudy (anonymous):

OpenStudy (agent0smith):

If you know the integral of 1/y is lny + C the integral of 1/(y+b) where b is any constant, is the almost the same thing. Integral of 1/(y+b) is ln(y+b)

OpenStudy (anonymous):

it's technically ln|y+4|

OpenStudy (anonymous):

so the answer is just ln|y+4| ?

OpenStudy (anonymous):

Yeah, unless it considers || the same as (), then use ()

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