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Find an integer, x, such that 5, 10, and x represent the lengths of the sides of an acute triangle.
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First x must satisfy 10-5 < x < 5+10 5 < x < 15 To have a triangle
Now you need an acute triangle, so how do you proceed?
If you take x near 5, then the angel opposite to 10 will be obtus
If you take x such that x^2 = 5^2 + 10^2=125, then the angle opposite to x will be 90 degrees
sqrt(125)=11.1803, try take x =11 and show that your triangle will be acute
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