Find the point on the terminal side of θ = -(3pi)/4 that has an x coordinate of -1
so the 3 different trig functions in terms of x and y are like this sin = y/hypotenuse cos = x/hypotenuse tan = y/x
do you know what the unit circle is?
no :/
ok google it, its going to help you understand this a lot more
makes a bit more sense but I still have no idea how to answer the question :P
ok so youre going to have to use a trig ratio that uses x, so its going to have to be either cos or tan since those are the only two that use x as one of their arguments
it has to be -1, so try to find a point on the unit circle where x is -1 and the angle is at 3pi/4 radians
hope this helps a bit more
i dont see any negative pi on the unit circle though
have you learned reference angles?
this is going to help you
i cant use the draw option for some reason...
well anyways since that 3pi/4 is positive you are going to have to move that same amount on the oposite direction
starting from angle 0
which is going to end up where 5pi/4 would be. That is -3pi/4 and this also works because the x is also negative in this part of the graph
those coordinate points are there when youre assuming that the hypotenuse of the triangle is 1. But in your case its not so just dont worry about them, im gonna see if i can get the graph thing working so that i can show you
okay
okay, so if I dont know the hypotenuse or y, how am I supposed to know what that point is?
inverse function?
use your trig functions to find them, you only need to know 1 value to find the others.
the inverse function is to find an angle
wait wouldnt I need tan? I need to solve for y, so tan(-3pi/4) = y/-1
that gives me .0411
is that right?
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