How do I make the system (y+x/2=8) (2y=-x+16) into slope form (y=mx+b)?
Can u make ur question more clear? Cant understand that system thingy
By equation those systems to y. Let's take the first example.
Its solving each system by graphing.. so first i have to make the equations into slope form (y=mx+b).
\[y + \frac{ x }{ 2 } =8 \] Therefore, \[y = -\frac{ 1 }{ 2 }x + 8\]
How did it become -1/2x+8?
well, let's make them individually ito tht form: for the first equation: \[y+\frac{ x }{ 2 }=8\] and sustracting x/2 on both sides: \[y=- \frac{ x }{ 2 }+8\] for the second: \[2y=-x+16\] dividing both sides by two: \[y=\frac{ -x+16 }{ 2 }\] simplifying: \[y=-\frac{ x }{ 2 }+8\]
By transposin it or like. \[y + \frac{ 1 }{ 2 }x -\frac{ 1 }{ 2 }x = \frac{ 1 }{ 2 }x + 8\]
Therefore \[y = \frac{ 1 }{ 2 }x + 8\]
Oh ok I get it now. So I guess its the same for the second one. Thanks Guys !
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