Question

A horse is extremely thirsty and is drinking out of a cylindrical trough that has a 3 meter diameter and a height of 1 meter, so if the horse is drinking 1/2 m^3/min, how fast is the water level decreasing when it is down to 1/3m?

Answer 1

@agent0smith

Answer 2

wow this is a bit hard what grade is this becuase im just in 8th

Answer 3

area is (3/2)^2 ft^2

Answer 4

in fraction?

Answer 5

oh i mean meters

Answer 6

ah, I see.. so how would i get it in meters?

Answer 7

fractions*

Answer 8

use unit cancellation. multiply by the foot/meter conversion twice

Answer 9

\[\large (\frac{ 3 }{ 2 })^2=\frac{ 9 }{ 4}m^2\]

Answer 10

Actually there are no feet here. it's all in meters :V

Answer 11

so, the fraction has gotta be in pi, no?

Answer 12

\[\huge \frac{\frac{ 1 }{ 2 }m^3/\min}{\frac{ 9 }{ 4 }m^2}=\]

Answer 13

oh yes i forgot pi

Answer 14

good call

Answer 15

1/9pi right?

Answer 16

\[\huge \frac{\frac{ 1 }{ 2 }m^3/\min}{\frac{ 9\pi^2 }{ 4 }m^2}=\]

Answer 17

2/81pi^2 right?

Answer 18

\[\huge \frac{\frac{ 1 }{ 2 }m^3}{\frac{ 9\pi^2 }{ 4 }m^2\min}=\frac{ \frac{ 1 }{ 2 } }{ \frac{ 9\pi^2 }{ 4 } }m/\min\]

Answer 19

ya, the answer above is what I'm getting, but it cant be right because of the square

Answer 20

=\[\Large \frac{ 2 }{ 9\pi^2 } m/\min\]

Answer 21

so, that the final or do i keep solving?

Answer 22

that should be it

Answer 23

it's not that because there can't be a squared

Answer 24

that's what it says on my paper anyways

Answer 25

oh you're right the pi isn't squared

Answer 26

dunno how i messed that up, but the rest is still correct

Answer 27

alrght, so how can we determine final?

Answer 28

i might have screwed up too by accident

Answer 29

\[\Large \frac{ 2 }{ 9\pi } m/\min\]

Answer 30

thanks again pal