Question

in the following reaction 451.4g of lea reacts with excess oxygen forming 387.9g of lead oxide. calculate the percent yield. 2Pb+O2-->2PbO

Answer 1

\(\sf \color{violet}{percent~yield = \frac{mass~of~ACTUAL~YIELD}{mass~of~THEORETICAL~YIELD}}\)

Answer 2

i did that but keep getting the wrong answer

Answer 3

Do you understand that the 387.9g of lead oxide is the actual yield, and you need to use stoichiometry to find the theoretical yield?

Answer 4

He should know that.

Answer 5

Just checking... :)