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What is the geometric mean of 6 and 13?
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Geometric mean = (a1 × a2 ... an)1/n (6 * 13)1/2 78 * 1/2 = 39
u r wrong
I did square it but got a really long decimal, so I thought it was wrong. √78
You could use an exponent, (78)^1/2
it's \[(a_1*a_2*...*a_n)^{1/n}\] The first attempt (=39) is incorrect. If you think about it, the geometric mean must be somewhere between the smallest and largest numbers.
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...I know its incorrect. I corrected it.
Yes, you did. I'm trying to help anyone reading this have an intuitive grasp of what the answer should (or shouldn't) be, to avoid any such future mistakes :-)
Lol so in a way, I showed what no to do (>.<) not exactly satisfying, but ok.
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