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Mathematics 12 Online
OpenStudy (lucaz):

when I restrict the domain of sin(x) I'm also restricting the range of arcsin(x) ?

OpenStudy (anonymous):

The question is a little vague, but i guess so.

OpenStudy (lucaz):

I want to be sure if I understand the inverse trig functions

OpenStudy (anonymous):

well give me an example, what do you mean by restricting the domain of sin(x)

OpenStudy (lucaz):

restrict to an interval [-pi/2 , pi/2]

OpenStudy (lucaz):

this would be the domain of sin(x)

OpenStudy (anonymous):

and then you take the arcsin with the same restrictions on the sin(x) itself?

OpenStudy (lucaz):

but this interval would be the range of arcsin(x)

OpenStudy (anonymous):

That would put a restriction on the range indeed, but not necessarily the same.

OpenStudy (lucaz):

not necessarily the same?

OpenStudy (anonymous):

Yes, for example if you have y=x^2 and you have a domain from [1,3] the range would be [1.9] but if you have 1/x^2 and the domain [1,3] the range would be [1,1/9]

OpenStudy (anonymous):

so a change to the function can mean a change to the range even if the domain stays the same.

OpenStudy (lucaz):

I see.. ok, thank you

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