Question

How do I graph sin/cos functions using points for: y=3/2cos(x+pi/2)

Answer 1

For x, plug in values like: -pi/2 , 0, pi/2, pi, 3pi/2
And see what the corresponding values of y turn out to be for each of those x's
Plot those points and connect the dots with a smooth curve.

Answer 2

the general form is

y = acos(bx + c)

a is the amplitude

the period of the curve is determined by 2pi/b

c is the phase shift...

so in your question

a = 3/2 so thats the amplitude

b = 1 so the period is 2pi ( it takes a distance of 2 pi to complete a full cycle)

c = pi/2 so the cos curve is shifted pi/2 to the left.

hope it helps

Answer 3

@campbell_st I did understand it, thing is, it requires me to give exact points and was not able to just provide that answer, but thank you. @BangkokGarrett that makes complete sense, I just hope it does work once I use the program to graph it. thanks!

Answer 4

Okay so I tried the first way, and was not any use since in the program I cannot use their calculator. Therefore, I need to find the points myself, how can I find the points using a this T chart