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Evaluate the indefinite integral.
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\[\int\limits \frac{ dt }{ \cos ^{2}t \sqrt{1+\tan t}}\]
let u=1+tan(t)
in general, letting u=(what's under the radical) is often the way to go here
For an interesting variation, you could try \(u^{2} = 1+\tan(t)\) and see where that leads.
@Turing Test du=sec^(2) x dx
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@TuringTest du=sec^(2) x dx
Write secant squared in terms of cosines, it might make more sense :o Remember your identity?
do you mean 1/cos^2 x
yes
is the answer \[\sqrt{1+\tan(t)}+C\]
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