Question

FIND THE VALUE OF:
sin 15 degrees

In trigonometry
ADDITION AND SUBTRACTION IDENTITIES

Answer 1

.6502

Answer 2

It's not like that

Answer 3

Try using a unit circle

Answer 4

\[\sin \frac{30}{2}=\sqrt{\frac{1-\cos 30}{2}}\]

Answer 5

\[\sin(15)=\sin(45-30)=\sin(45)\cos(30)-\cos(45)(\sin(30)\]

Answer 6

\[=\frac{ 1 }{ \sqrt{2} }*\frac{ \sqrt{3} }{ 2 }-\frac{ 1 }{ \sqrt{2} }*\frac{ 1 }{ 2 }\]

Answer 7

Which is which
@Mertsj @mustafa2014

Answer 8

$$
\sin 15=\sin ( 45-30)=\sin(45)\cos(30)-\cos(45)\sin(30)\\
=\sqrt2/2\times(\sqrt3/2)-\sqrt2/2\times(1/2)\\
=\sqrt2/2\cfrac{\sqrt3-1}{2}\\
=\sqrt2\cfrac{\sqrt3-1}{4}\\
=\sqrt2\cfrac{\sqrt3-1}{2\times 2}\\
=\cfrac{\sqrt3-1}{\sqrt2\times 2}\\
$$

Answer 9

Cant i use sin(60-45)???

Answer 10

you can use it :)

Answer 11

What other values could i use @mustafa2014