Question

Solve -63x + 7y + 49 = 0 for y

Answer 1

There are several ways to go about this. All will attempt to isolate the y so that it ends up by itself, and positive on the left of the equal sign.

Answer 2

\[-63x+7y+49=0\]
\[7y=63x-49\]
\[(7y=63x-49)\div7\]
\[y=9x-7\]

Answer 3

@kas9987 its right! thank you

Answer 4

Using algebra, I would first divide all terms by 7. This would result in:
-9x + y + 7 = 0
Next I would add 9x -7 to both sides of the equal sign, getting y=9x-7.
There you have it, y by itself on the left and 9x -7 on the right.

Answer 5

@mariruiz no problem