Triangle ABC has vertices A(1,2), B(7,0) and C(3,-2).
Prove triangle ABC is an isosceles triangle.
Is this triangle a right triangle?
Lengths of: (Round to nearest hundredths)
AB:
BC:
CA:
Right Triangle? Yes or no?
Any explanation is appreciated. Thank you!

Question

Triangle ABC has vertices A(1,2), B(7,0) and C(3,-2).
Prove triangle ABC is an isosceles triangle.
Is this triangle a right triangle?
Lengths of: (Round to nearest hundredths)
AB:
BC:
CA:
Right Triangle? Yes or no?
Any explanation is appreciated. Thank you!

anonymous · Answer

$$d=\sqrt{\left( x2-x1 \right)^2+\left( y2-y1 \right)^2}$$
using this formula find AB,BC,CA 
see if any two sides are equal.(isosceles triangle)
or sum of squares of two sides =square of third side,then Right angled triangle.