Question

If the margin of error in an estimate for the mean weight of a shipment is + or -2 pounds at a confidence level of 95 percent, what will be the margin of error at a confidence level of 98 percent? Be sure to show how you arrived at your answer.

Answer 1

we can use that equation we used earlier

Answer 2

x bar + - margin of error.

margin of error = z* st.dev / sqrt(n)

Answer 3

i got it haha

Answer 4

z* for 95% confidence level is 1.960
z* for 98% confidence is 2.326

so we are given that 1.960 * st.dev / sqrt(n) = 2

Answer 5

Thanks! @perl

Answer 6

what did you get for the answer

Answer 7

i got 2

Answer 8

st.dev / sqrt(n) = 2/ 1.960
so
2.326 * 2/ 1.960 = 2.37 ,

Answer 9

i rounded haha but i got something close i got 2.47

Answer 10

should be 2.37 pounds

Answer 11

should we round?

Answer 12

yes no haha

Answer 13

yes no?

Answer 14

yes no sounds like a maybe ;)

Answer 15

You're the best @perl

Answer 16

well i dont think the answer is 2 because then the confidence level didn't change, right?

Answer 17

maybe you can help me with some more stats if ever do get stumped?

Answer 18

sure :)

Answer 19

i would love that