Question

A bullet of mass 45 g is fired at a speed of 220 m/s into a 5.0-kg sandbag hanging from a string from the ceiling. The sandbag absorbs the bullet and begins to swing. To what maximum vertical height will it rise? Hint: Energy is not conserved as the bullet enters the bag but is conserved after the bullet comes to rest in the bag and the bag is swinging upward

Answer 1

(m1*V1)=(m1+m2)Vnew Vnew=1.96m/s After that I'm stuck

Answer 2

You may use the principle of censervation of energy to find the height.
\[E=E _{p}+E _{k}=0\]
\[E _{p}=m \times g \times h\]
\[E _{k}=\frac{ 1 }{ 2 } \times m \times v ^{2}\]
\[E _{p}=-E _{k}\]

replacing the data in the formulas, you might obtain the height of the sandbag.