how can we obtain 3-nitro aniline from nitrobenzene?
Well, you might want to think about what nitro substituent is - ortho, meta, para director? electron w/drawing or donating?
its electron withdrawing, so its a meta director...
Knowing that, I would start by reducing nitrobenzene \(\rightarrow\) aniline first. Then, nitrate the benzene to add nitrobenzene in meta position. Does that make sense?
The thing is the amino group in aniline is electron donating, hence ortho-para directing, so if i reduce the nitro group to the amino group and then nitrate it, its gonna direct the new nitro group to the ortho/para positions, giving 2 and 4 nitro aniline, and not the desired 3 nitro aniline.
nitrile group is electron withdrawing CN:
nah, nitro, aniline is C6H6NH2, not CN: .So the amino group is electron donating.
Are you sure? I think CN:\(^-\) is EDG
CN: is the nitrile(cyano) group, and -NO2 is the nitro group
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