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zepdrix (zepdrix):
\[\Large\bf\sf x^r\cdot e^{sx}\]We need to take the derivative of this with respect to x?
OpenStudy (anonymous):
yes. The r throws me off
zepdrix (zepdrix):
TEAM JACOBBBBBB!!!!
zepdrix (zepdrix):
I'm jkjk jk lol.. ive never actually seen the movies.. just read your profile XD trying to stir up trouble.
zepdrix (zepdrix):
ok ok anyway, the problem here.. let's see
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zepdrix (zepdrix):
\[\Large\bf\sf \left(x^r\cdot e^{sx}\right)'\quad=\quad \color{royalblue}{\left(x^r\right)'}e^{sx}+x^r\color{royalblue}{\left(e^{sx}\right)'}\]We have the product of two functions of x.
So here is our product rule setup.
We need to take the derivative of the blue parts.
The first one is giving you trouble?
OpenStudy (anonymous):
yes, the first part
OpenStudy (anonymous):
Would it be 0 because of r or no?
zepdrix (zepdrix):
Just power rule silly! :O
zepdrix (zepdrix):
\[\Large\bf\sf (x^5)'\quad=\quad 5x^{5-1}\]
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