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Mathematics 21 Online
OpenStudy (anonymous):

how do you find the magnitude and direction of the resultant vector from the diagram (it is scanned.)

OpenStudy (anonymous):

OpenStudy (anonymous):

#8

OpenStudy (mathmale):

This is a multi-step problem. Breaking the problem into parts, find the resultant vector. Then find the length of this resultant vector. How have you found resultant vectors in the past? Once you have a vector, any vector, how do you find the length of the vector?

OpenStudy (anonymous):

dont you need coordinates of the endpoints to do that?

random231 (random231):

read this crefully: http://easycalculation.com/physics/classical-physics/resultant-vector.php

OpenStudy (phi):

use x= r cos(A) and y = r sin(A) where r is the length, and A is the angle find the <x,y> values of both vectors add the two vectors then find the length r= sqr(x^2 + y^2) and angle A = atan(y/x)

OpenStudy (mathmale):

cssc: Yes and no. Finding the endpoints might make the problem a bit clearer, but all you need to do is to use the formulas for x and y which our friend phi has typed in above. For example, if we want the horizontal component of the resultant vector in this problem, we'd find the component in the negative x direction of the 11N force, then the component of the 10N vector in the positive x direction, and then add those two horiz. comps. together. To help you get started, the comp of the resultant in the neg. x direction is (11N)cos 144 deg 32 min. Find the comp of the res. in the pos. x direction now.

OpenStudy (anonymous):

thnk yall!!!!

OpenStudy (mathmale):

It'll take some work on your part to finish this problem, but you do have potential helpers standing by. Going to finish the problem or not?

OpenStudy (anonymous):

thank you. I wil ask for any additional help i need thank you so much :)

OpenStudy (anonymous):

@mathmale if you give phi a medal, i can give u a medal too :D

OpenStudy (anonymous):

thank you so much!!! :) and i got the answer i think :)

OpenStudy (anonymous):

@phi hey, what did you mean by atan? that the inverse of tan? or what? thank you

OpenStudy (anonymous):

nevermind! thanks so much!!! :D

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